NCERT Solutions For Class 6 Maths Chapter 2 Whole Numbers Exercise 2.2 has questions related to properties of whole numbers, like closure property, commutativity, associativity, distributivity and identity, solved by Math experts at TEXTUAL SOLUTION. The natural numbers along with zero form whole numbers. The second exercise of this chapter has 7 main questions related to the properties of whole numbers. Following the NCERT Solutions of Class 6 Chapter 2 will help students to understand how to solve the different types of questions related to the topics mentioned above, that could be asked in the exam.
NCERT Solution for Class 6 Chapter 2 Math Whole Numbers Exercise 2.2
1. Find the sum by suitable rearrangement :
(a) 837 + 208 + 363 (b) 1962 + 453 + 1538 + 647
Solutions :
(a) (837 + 363) + 208
= 1200 + 208 = 1408
(b) (1962 + 1538) + (453 + 647)
= 3500 + 1100
= 4600
2. Find the product by suitable rearrangement :
(a) 2 × 1768 × 50 (b) 4 × 166 × 25 (c) 8 × 291 × 125
(d) 625 × 279 × 16 (e) 285 × 5 × 60 (f) 125 × 40 × 8 × 25
Solutions :
(a) 2 × 1768 × 50
= (2 × 50) × 1768
= 100 × 1768
= 176800
(b) 4 × 166 × 25
= (4 × 25) × 166
= 100 × 166
= 16600
(c) 8 × 291 × 125
= (8 × 125) × 291
= 1000 × 291
= 291000
(d) 625 × 279 × 16
= (625 × 16) × 279
= 10000 × 279
= 2790000
(e) 285 × 5 × 60
= 285 × (5 × 60)
= 285 × 300
= 85500
(f) 125 × 40 × 8 × 25
= (125 × 8) × (40 × 25)
= 1000 × 1000
= 1000000
3. Find the value of the following :
(a) 297 × 17 + 297 × 3 (b) 54279 × 92 + 8 × 54279
(c) 81265 × 169 - 81265 × 69 (d) 3845 × 5 × 782 + 769 × 25 × 218
Solutions :
(a) 297 × 17 + 297 × 3
= 297 × (17 + 3)
= 297 × 20
= 5940
(b) 54279 × 92 + 8 × 54279
= 54279 × (92 + 8)
= 54279 × 100
= 5427900
(c) 81265 × 169 - 81265 × 69
= 81265 × (169 - 69)
= 81265 × 100
= 8126500
(d) 3845 × 5 × 782 + 769 × 25 × 218
= 3845 × 5 × 782 + (769 × 5) × 218
= 3845 × 5 × 782 + 3845 × 5 × 218
= (3845 × 5) × (782 + 218)
= 19225 × 1000
= 19225000
4. Find the product using suitable properties.
(a) 738 × 103 (b) 854 × 102 (c) 258 × 1008 (d) 1005 × 168
Solutions :
(a) 738 × 103
= 738 × (100 + 3)
= 738 × 100 + 738 × 3
= 73800 + 2214
= 76014
(b) 854 × 102
= 854 × (100 + 2)
= 854 × 100 + 854 × 2
= 85400 + 1708
= 87108
(c) 258 × 1008
= 258 × (1000 + 8)
= 258 × 1000 + 258 × 8
= 258000 + 2064
= 260064
(d) 1005 × 168
= (1000 + 5) × 168
= 1000 × 168 + 5 × 168
= 168000 + 840
= 168840
5. A taxidriver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs ₹44 per litre, how much did he spend in all on petrol ?
Solution :
Petrol filled on Monday and Tuesday = 40 litres + 50 litres = 90 litres
Cost of petrol = ₹44 per litre
∴ 90 × ₹44 = ₹ 3960
6. A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs Rs 15 per litre, how much money is due to the vendor per day ?
Solution :
Milk supplied to a hotel in the morning and evening = 32 litres + 68 litres = 100 litres
Money due to the vendor per day = 100 × Rs 15 = Rs 1500
7. Match the following :
| (i) 425 × 136 = 425 × (6 + 30 + 100) |
(a) Commutativity under multiplication. |
| (ii) 2 × 49 × 50 = 2 × 50 × 49 |
(b) Commutativity under addition. |
| (iii) 80 + 2005 + 20 = 80 + 20 + 2005 |
(c) Distributivity of multiplication over addition. |
Solution :
| (i) 425 × 136 = 425 × (6 + 30 + 100) |
(c) Distributivity of multiplication over addition. |
| (ii) 2 × 49 × 50 = 2 × 50 × 49 |
(a) Commutativity of multiplication. |
| (iii) 80 + 2005 + 20 = 80 + 20 + 2005 |
(b) Commutatiity of addition. |
