Class : 6
Subject : Mathematics
Chapter : 1 - Knowing Our Numbers
1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.
Solution :
Number of tickts sold on 1st day = 1094
Number of tickets sold on 2nd day = 1812
Number of tickets sold on 3rd day = 2050
Number of tickets sold on 4th day = 2751
Hence, total number of tickets sold on all the four days
= 1094 + 1812 + 2050 + 2751
= 7707 tickets
2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need ?
Solution :
Shekhar scored = 6980 runs
He wants to complete = 10000 runs
Runs need to score more
= 10000 - 6980
= 3020
Hence, he need 3020 more runs to score.
3. In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election ?
Solution :
No. of votes secured by the successful candidate = 577500
No. of votes secured by his rival = 348700
Margin by which he won the election
= 577500 - 348700
= 228800 votes
∴ Successful candidate won the election by 228800 votes
4. Kirti bookstore sold books worth ₹2,85,891 in the first week of June and books worth ₹4,00,768 in the second week of the month. How much was the sale for the two weeks together ? In which week was the sale greater and by how much ?
Solution :
Sale of books in the first week
= Rs 285891
Sale of books in the second week
= Rs 400768
Sale of books in the two weeks
= Rs 285891 + Rs 400768
= Rs 686659
∴ Sale in two weeks is of Rs 686659
Since 400768 > 285891
∴ Sale in the second week is greater.
Difference in the sales amount
= Rs 400768 - Rs 285891
= Rs 114877
∴ Sale in the second week is more by Rs 114877
5. Find the difference between the greatest and the least 5-digit number that can be written using the digits 6, 2, 7, 4, 3 each only once.
Solution :
Using the digits 6, 2, 7, 4 and 3, we get
Greatest number = 76432
Smallest number = 23467
Their difference = 76432 - 23467
= 52965
∴ Difference between the greatest and least number is 52965.
6. A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006 ?
Solution :
Number of screws manufactured in a day
= 2,825
Since, January month has 31 days
Hence, number of screws manufactured in January
= 31 × 2825
= 87575
Hence, machine produce 87575
Hence, machine produce 87575 screws in the month of January 2006
7. A merchant had ₹78,592 with her. She placed an order for purchasing 40 radio sets at ₹ 1200 each. How much money will remain with her after the purchase.
Solution :
Total money the merchant had = Rs 78592
Number of radio sets she placed an order for purchasing = 40 radio sets
Cost of each radio set = Rs 1200
So, cost of 40 radio sets
= Rs 1200 × 40
= Rs 48000
Money left with the merchant
Rs 78592 - Rs 48000
Rs 30592
Hence, money left the merchant after purchasing radio sets is 30592
8. A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer ? (Hint : Do you need to do both the multiplications ?)
Solution :
Difference between 65 and 56 i.e., (65 - 56 = 9)
The difference between the correct and incorrect answer
= 7236 × 9
= 65124
Hence, by 65124, the answer was greater than the correct answer.
9. To stitch a shirt, 2m 15cm cloth is needed. Out of 40m cloth, how many shirts can be stitched and how much cloth will remain ?
(Hint : Convert data in cm)
Solution :
Given:
Total length of cloth = 40m
= 40 × 100 cm
= 4000 cm
cloth required to stitch one shirt
= 2m 15 cm
= 2 × 100 + 15 cm
= 215 cm
Number of shirts that can be stitched out of 4000 cm = 4000/215 = 18 shirts
Hence 18 shirts can be stitched out of 40m and 1m 30 cm of cloth is left out
10. Medicine is packed in boxes, each weighing 4 kg 500g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg ?
Solution :
weight of one box = 4 kg 500g = 4 × 1000 + 500 = 4500g
Maximim weight carried by the van = 800 kg = 800 × 1000 = 800000g
Hence, number of boxes that can be loaded in the van = 800000/4500 = 177 boxes
11. The distance between the school and a student's house is 1 km 875m. Everyday she walks both the ways. Find the total distance covered by her in six days.
Solution :
Distance covered between school and house = 1km 875m = 1000 + 875 = 1875m
Since, the student walk both ways.
Hence, distance travelled by the student in one day = 2 × 1875 = 3750m
Distance travelled by the student in six day = 3750m × 6 = 22500m = 22km 500m
∴ Total distance covered by the student in six days is 22 km and 500m
12. A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25ml capacity, can it be filled ?
Solution :
Quantity of curd in the vessel = 4l 500ml = 4 × 1000 + 500 = 4500ml
Capacity of 1 glass = 25ml
∴ number of glasses that can be filled with curd = 4500/25 = 180 glasses
Hence, 180 glasses can be filled with curd.